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x^2+7.5x+10=0
a = 1; b = 7.5; c = +10;
Δ = b2-4ac
Δ = 7.52-4·1·10
Δ = 16.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.5)-\sqrt{16.25}}{2*1}=\frac{-7.5-\sqrt{16.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.5)+\sqrt{16.25}}{2*1}=\frac{-7.5+\sqrt{16.25}}{2} $
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